6(1+2j)=

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Solution for 6(1+2j)= equation: 



6(1+2j)=

We move all terms to the left:

6(1+2j)-()=0

We add all the numbers together, and all the variables

6(2j+1)-()=0

We add all the numbers together, and all the variables

6(2j+1)=0

We multiply parentheses

12j+6=0

We move all terms containing j to the left, all other terms to the right

12j=-6

j=-6/12

j=-1/2

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