4(x+2)=16+2(x-1(

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Solution for 4(x+2)=16+2(x-1( equation: 



4(x+2)=16+2(x-1(

We move all terms to the left:

4(x+2)-(16+2(x-1()=0

We multiply parentheses

4x-(16+2(x-1()+8=0

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