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10(a-1)=4(2a+3)
We move all terms to the left:
10(a-1)-(4(2a+3))=0
We multiply parentheses
10a-(4(2a+3))-10=0
We calculate terms in parentheses: -(4(2a+3)), so:We get rid of parentheses
4(2a+3)
We multiply parentheses
8a+12
Back to the equation:
-(8a+12)
10a-8a-12-10=0
We add all the numbers together, and all the variables
2a-22=0
We move all terms containing a to the left, all other terms to the right
2a=22
a=22/2
a=11
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