4(x+1)+5=(x+1)+x

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Solution for 4(x+1)+5=(x+1)+x equation: 



4(x+1)+5=(x+1)+x

We move all terms to the left:

4(x+1)+5-((x+1)+x)=0

We multiply parentheses

4x-((x+1)+x)+4+5=0



We calculate terms in parentheses: -((x+1)+x), so:

(x+1)+x

We add all the numbers together, and all the variables

x+(x+1)

We get rid of parentheses

x+x+1

We add all the numbers together, and all the variables

2x+1

Back to the equation:

-(2x+1)



We add all the numbers together, and all the variables

4x-(2x+1)+9=0

We get rid of parentheses

4x-2x-1+9=0

We add all the numbers together, and all the variables

2x+8=0

We move all terms containing x to the left, all other terms to the right

2x=-8

x=-8/2

x=-4

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