-6(x+1)+8x=2(x+3)

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Solution for -6(x+1)+8x=2(x+3) equation: 



-6(x+1)+8x=2(x+3)

We move all terms to the left:

-6(x+1)+8x-(2(x+3))=0

We add all the numbers together, and all the variables

8x-6(x+1)-(2(x+3))=0

We multiply parentheses

8x-6x-(2(x+3))-6=0



We calculate terms in parentheses: -(2(x+3)), so:

2(x+3)

We multiply parentheses

2x+6

Back to the equation:

-(2x+6)



We add all the numbers together, and all the variables

2x-(2x+6)-6=0

We get rid of parentheses

2x-2x-6-6=0

We add all the numbers together, and all the variables

-12!=0

There is no solution for this equation

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