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3(x-2)+4=5(x-1)+x
We move all terms to the left:
3(x-2)+4-(5(x-1)+x)=0
We multiply parentheses
3x-(5(x-1)+x)-6+4=0
We calculate terms in parentheses: -(5(x-1)+x), so:We add all the numbers together, and all the variables
5(x-1)+x
We add all the numbers together, and all the variables
x+5(x-1)
We multiply parentheses
x+5x-5
We add all the numbers together, and all the variables
6x-5
Back to the equation:
-(6x-5)
3x-(6x-5)-2=0
We get rid of parentheses
3x-6x+5-2=0
We add all the numbers together, and all the variables
-3x+3=0
We move all terms containing x to the left, all other terms to the right
-3x=-3
x=-3/-3
x=1
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