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5(g-4)=7(g2+1)
We move all terms to the left:
5(g-4)-(7(g2+1))=0
We add all the numbers together, and all the variables
-(7(+g^2+1))+5(g-4)=0
We multiply parentheses
-(7(+g^2+1))+5g-20=0
We calculate terms in parentheses: -(7(+g^2+1)), so:We add all the numbers together, and all the variables
7(+g^2+1)
We multiply parentheses
7g^2+7
Back to the equation:
-(7g^2+7)
5g-(7g^2+7)-20=0
We get rid of parentheses
-7g^2+5g-7-20=0
We add all the numbers together, and all the variables
-7g^2+5g-27=0
a = -7; b = 5; c = -27;
Δ = b2-4ac
Δ = 52-4·(-7)·(-27)
Δ = -731
Delta is less than zero, so there is no solution for the equation
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