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3(3x-5)=2(x-10)-6
We move all terms to the left:
3(3x-5)-(2(x-10)-6)=0
We multiply parentheses
9x-(2(x-10)-6)-15=0
We calculate terms in parentheses: -(2(x-10)-6), so:We get rid of parentheses
2(x-10)-6
We multiply parentheses
2x-20-6
We add all the numbers together, and all the variables
2x-26
Back to the equation:
-(2x-26)
9x-2x+26-15=0
We add all the numbers together, and all the variables
7x+11=0
We move all terms containing x to the left, all other terms to the right
7x=-11
x=-11/7
x=-1+4/7
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