4(v+5)=-4(4v-9)+2v

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Solution for 4(v+5)=-4(4v-9)+2v equation: 



4(v+5)=-4(4v-9)+2v

We move all terms to the left:

4(v+5)-(-4(4v-9)+2v)=0

We multiply parentheses

4v-(-4(4v-9)+2v)+20=0



We calculate terms in parentheses: -(-4(4v-9)+2v), so:

-4(4v-9)+2v

We add all the numbers together, and all the variables

2v-4(4v-9)

We multiply parentheses

2v-16v+36

We add all the numbers together, and all the variables

-14v+36

Back to the equation:

-(-14v+36)



We get rid of parentheses

4v+14v-36+20=0

We add all the numbers together, and all the variables

18v-16=0

We move all terms containing v to the left, all other terms to the right

18v=16

v=16/18

v=8/9

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