3(u-1)-5=-4(-3u+3)-3u

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Solution for 3(u-1)-5=-4(-3u+3)-3u equation: 



3(u-1)-5=-4(-3u+3)-3u

We move all terms to the left:

3(u-1)-5-(-4(-3u+3)-3u)=0

We multiply parentheses

3u-(-4(-3u+3)-3u)-3-5=0



We calculate terms in parentheses: -(-4(-3u+3)-3u), so:

-4(-3u+3)-3u

We add all the numbers together, and all the variables

-3u-4(-3u+3)

We multiply parentheses

-3u+12u-12

We add all the numbers together, and all the variables

9u-12

Back to the equation:

-(9u-12)



We add all the numbers together, and all the variables

3u-(9u-12)-8=0

We get rid of parentheses

3u-9u+12-8=0

We add all the numbers together, and all the variables

-6u+4=0

We move all terms containing u to the left, all other terms to the right

-6u=-4

u=-4/-6

u=2/3

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