-4(2v-1)+4v=8+2(2v-1)

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Solution for -4(2v-1)+4v=8+2(2v-1) equation: 



-4(2v-1)+4v=8+2(2v-1)

We move all terms to the left:

-4(2v-1)+4v-(8+2(2v-1))=0

We add all the numbers together, and all the variables

4v-4(2v-1)-(8+2(2v-1))=0

We multiply parentheses

4v-8v-(8+2(2v-1))+4=0



We calculate terms in parentheses: -(8+2(2v-1)), so:

8+2(2v-1)

determiningTheFunctionDomain
2(2v-1)+8

We multiply parentheses

4v-2+8

We add all the numbers together, and all the variables

4v+6

Back to the equation:

-(4v+6)



We add all the numbers together, and all the variables

-4v-(4v+6)+4=0

We get rid of parentheses

-4v-4v-6+4=0

We add all the numbers together, and all the variables

-8v-2=0

We move all terms containing v to the left, all other terms to the right

-8v=2

v=2/-8

v=-1/4

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