4(t-2)=8(t-3)-12

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Solution for 4(t-2)=8(t-3)-12 equation: 



4(t-2)=8(t-3)-12

We move all terms to the left:

4(t-2)-(8(t-3)-12)=0

We multiply parentheses

4t-(8(t-3)-12)-8=0



We calculate terms in parentheses: -(8(t-3)-12), so:

8(t-3)-12

We multiply parentheses

8t-24-12

We add all the numbers together, and all the variables

8t-36

Back to the equation:

-(8t-36)



We get rid of parentheses

4t-8t+36-8=0

We add all the numbers together, and all the variables

-4t+28=0

We move all terms containing t to the left, all other terms to the right

-4t=-28

t=-28/-4

t=+7

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