4(r+5)-17=5(r-7)+29

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Solution for 4(r+5)-17=5(r-7)+29 equation: 



4(r+5)-17=5(r-7)+29

We move all terms to the left:

4(r+5)-17-(5(r-7)+29)=0

We multiply parentheses

4r-(5(r-7)+29)+20-17=0



We calculate terms in parentheses: -(5(r-7)+29), so:

5(r-7)+29

We multiply parentheses

5r-35+29

We add all the numbers together, and all the variables

5r-6

Back to the equation:

-(5r-6)



We add all the numbers together, and all the variables

4r-(5r-6)+3=0

We get rid of parentheses

4r-5r+6+3=0

We add all the numbers together, and all the variables

-1r+9=0

We move all terms containing r to the left, all other terms to the right

-r=-9

r=-9/-1

r=+9

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