1000=19(1-4x)+15x+10(2+2x)

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Solution for 1000=19(1-4x)+15x+10(2+2x) equation: 



1000=19(1-4x)+15x+10(2+2x)

We move all terms to the left:

1000-(19(1-4x)+15x+10(2+2x))=0

We add all the numbers together, and all the variables

-(19(-4x+1)+15x+10(2x+2))+1000=0



We calculate terms in parentheses: -(19(-4x+1)+15x+10(2x+2)), so:

19(-4x+1)+15x+10(2x+2)

We add all the numbers together, and all the variables

15x+19(-4x+1)+10(2x+2)

We multiply parentheses

15x-76x+20x+19+20

We add all the numbers together, and all the variables

-41x+39

Back to the equation:

-(-41x+39)



We get rid of parentheses

41x-39+1000=0

We add all the numbers together, and all the variables

41x+961=0

We move all terms containing x to the left, all other terms to the right

41x=-961

x=-961/41

x=-23+18/41

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