-4(2u-1)+5u=7+3(5u-5)

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Solution for -4(2u-1)+5u=7+3(5u-5) equation: 



-4(2u-1)+5u=7+3(5u-5)

We move all terms to the left:

-4(2u-1)+5u-(7+3(5u-5))=0

We add all the numbers together, and all the variables

5u-4(2u-1)-(7+3(5u-5))=0

We multiply parentheses

5u-8u-(7+3(5u-5))+4=0



We calculate terms in parentheses: -(7+3(5u-5)), so:

7+3(5u-5)

determiningTheFunctionDomain
3(5u-5)+7

We multiply parentheses

15u-15+7

We add all the numbers together, and all the variables

15u-8

Back to the equation:

-(15u-8)



We add all the numbers together, and all the variables

-3u-(15u-8)+4=0

We get rid of parentheses

-3u-15u+8+4=0

We add all the numbers together, and all the variables

-18u+12=0

We move all terms containing u to the left, all other terms to the right

-18u=-12

u=-12/-18

u=2/3

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