4(r+20)=3r-34

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Solution for 4(r+20)=3r-34 equation:



4(r+20)=3r-34
We move all terms to the left:
4(r+20)-(3r-34)=0
We multiply parentheses
4r-(3r-34)+80=0
We get rid of parentheses
4r-3r+34+80=0
We add all the numbers together, and all the variables
r+114=0
We move all terms containing r to the left, all other terms to the right
r=-114

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