2/3x-5=3/4x+20

Solution for 2/3x-5=3/4x+20 equation:

2/3x-5=3/4x+20

We move all terms to the left:

2/3x-5-(3/4x+20)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 4x+20)!=0

x∈R


We get rid of parentheses

2/3x-3/4x-20-5=0

We calculate fractions


8x/12x^2+(-9x)/12x^2-20-5=0

We add all the numbers together, and all the variables

8x/12x^2+(-9x)/12x^2-25=0

We multiply all the terms by the denominator


8x+(-9x)-25*12x^2=0

Wy multiply elements

-300x^2+8x+(-9x)=0

We get rid of parentheses

-300x^2+8x-9x=0

We add all the numbers together, and all the variables

-300x^2-1x=0

a = -300; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-300)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-300}=\frac{0}{-600}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-300}=\frac{2}{-600}
=-1/300
$