4(2c+13)=80

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Solution for 4(2c+13)=80 equation: 



4(2c+13)=80

We move all terms to the left:

4(2c+13)-(80)=0

We multiply parentheses

8c+52-80=0

We add all the numbers together, and all the variables

8c-28=0

We move all terms containing c to the left, all other terms to the right

8c=28

c=28/8

c=3+1/2

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