4(n-1)+3=3(2n-1)-n+2

Solution for 4(n-1)+3=3(2n-1)-n+2 equation:

4(n-1)+3=3(2n-1)-n+2

We move all terms to the left:

4(n-1)+3-(3(2n-1)-n+2)=0

We multiply parentheses

4n-(3(2n-1)-n+2)-4+3=0


We calculate terms in parentheses: -(3(2n-1)-n+2), so:

3(2n-1)-n+2

We add all the numbers together, and all the variables

-1n+3(2n-1)+2

We multiply parentheses

-1n+6n-3+2

We add all the numbers together, and all the variables

5n-1

Back to the equation:

-(5n-1)


We add all the numbers together, and all the variables

4n-(5n-1)-1=0

We get rid of parentheses

4n-5n+1-1=0

We add all the numbers together, and all the variables

-n=0

n=0/-1

n=0