(5+v)(3v+8)=0

Solution for (5+v)(3v+8)=0 equation:

(5+v)(3v+8)=0

We add all the numbers together, and all the variables

(v+5)(3v+8)=0

We multiply parentheses ..

(+3v^2+8v+15v+40)=0

We get rid of parentheses

3v^2+8v+15v+40=0

We add all the numbers together, and all the variables

3v^2+23v+40=0

a = 3; b = 23; c = +40;
Δ = b2-4ac
Δ = 232-4·3·40
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-7}{2*3}=\frac{-30}{6}
=-5
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+7}{2*3}=\frac{-16}{6}
=-2+2/3
$