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X2+9X=7
We move all terms to the left:
X2+9X-(7)=0
We add all the numbers together, and all the variables
X^2+9X-7=0
a = 1; b = 9; c = -7;
Δ = b2-4ac
Δ = 92-4·1·(-7)
Δ = 109
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{109}}{2*1}=\frac{-9-\sqrt{109}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{109}}{2*1}=\frac{-9+\sqrt{109}}{2} $
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