22=3(7c-4)

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Solution for 22=3(7c-4) equation: 



22=3(7c-4)

We move all terms to the left:

22-(3(7c-4))=0



We calculate terms in parentheses: -(3(7c-4)), so:

3(7c-4)

We multiply parentheses

21c-12

Back to the equation:

-(21c-12)



We get rid of parentheses

-21c+12+22=0

We add all the numbers together, and all the variables

-21c+34=0

We move all terms containing c to the left, all other terms to the right

-21c=-34

c=-34/-21

c=1+13/21

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