4(n+4)=2(n+4)-6

Solution for 4(n+4)=2(n+4)-6 equation:

4(n+4)=2(n+4)-6

We move all terms to the left:

4(n+4)-(2(n+4)-6)=0

We multiply parentheses

4n-(2(n+4)-6)+16=0


We calculate terms in parentheses: -(2(n+4)-6), so:

2(n+4)-6

We multiply parentheses

2n+8-6

We add all the numbers together, and all the variables

2n+2

Back to the equation:

-(2n+2)


We get rid of parentheses

4n-2n-2+16=0

We add all the numbers together, and all the variables

2n+14=0

We move all terms containing n to the left, all other terms to the right

2n=-14

n=-14/2

n=-7