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3600=2/3(x+x+900)
We move all terms to the left:
3600-(2/3(x+x+900))=0
Domain of the equation: 3(x+x+900))!=0We add all the numbers together, and all the variables
x∈R
-(2/3(2x+900))+3600=0
We multiply all the terms by the denominator
-(2+3600*3(2x+900))=0
We calculate terms in parentheses: -(2+3600*3(2x+900)), so:We add all the numbers together, and all the variables
2+3600*3(2x+900)
determiningTheFunctionDomain 3600*3(2x+900)+2
Wy multiply elements
10800x(2+2
Back to the equation:
-(10800x(2+2)
-(10800x4=0
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