7(n+2)=7(4-n)

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Solution for 7(n+2)=7(4-n) equation: 



7(n+2)=7(4-n)

We move all terms to the left:

7(n+2)-(7(4-n))=0

We add all the numbers together, and all the variables

7(n+2)-(7(-1n+4))=0

We multiply parentheses

7n-(7(-1n+4))+14=0



We calculate terms in parentheses: -(7(-1n+4)), so:

7(-1n+4)

We multiply parentheses

-7n+28

Back to the equation:

-(-7n+28)



We get rid of parentheses

7n+7n-28+14=0

We add all the numbers together, and all the variables

14n-14=0

We move all terms containing n to the left, all other terms to the right

14n=14

n=14/14

n=1

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