4(n+2)+n-1=2(n+7)+5

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Solution for 4(n+2)+n-1=2(n+7)+5 equation: 



4(n+2)+n-1=2(n+7)+5

We move all terms to the left:

4(n+2)+n-1-(2(n+7)+5)=0

We add all the numbers together, and all the variables

n+4(n+2)-(2(n+7)+5)-1=0

We multiply parentheses

n+4n-(2(n+7)+5)+8-1=0



We calculate terms in parentheses: -(2(n+7)+5), so:

2(n+7)+5

We multiply parentheses

2n+14+5

We add all the numbers together, and all the variables

2n+19

Back to the equation:

-(2n+19)



We add all the numbers together, and all the variables

5n-(2n+19)+7=0

We get rid of parentheses

5n-2n-19+7=0

We add all the numbers together, and all the variables

3n-12=0

We move all terms containing n to the left, all other terms to the right

3n=12

n=12/3

n=4

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