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(3x-13)=(x+39)
We move all terms to the left:
(3x-13)-((x+39))=0
We get rid of parentheses
3x-((x+39))-13=0
We calculate terms in parentheses: -((x+39)), so:We get rid of parentheses
(x+39)
We get rid of parentheses
x+39
Back to the equation:
-(x+39)
3x-x-39-13=0
We add all the numbers together, and all the variables
2x-52=0
We move all terms containing x to the left, all other terms to the right
2x=52
x=52/2
x=26
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