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(-3)=-9x^2-5x+38
We move all terms to the left:
(-3)-(-9x^2-5x+38)=0
We add all the numbers together, and all the variables
-(-9x^2-5x+38)-3=0
We get rid of parentheses
9x^2+5x-38-3=0
We add all the numbers together, and all the variables
9x^2+5x-41=0
a = 9; b = 5; c = -41;
Δ = b2-4ac
Δ = 52-4·9·(-41)
Δ = 1501
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{1501}}{2*9}=\frac{-5-\sqrt{1501}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{1501}}{2*9}=\frac{-5+\sqrt{1501}}{18} $
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