4(k-2)-6=4k-(3k-2)

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Solution for 4(k-2)-6=4k-(3k-2) equation: 



4(k-2)-6=4k-(3k-2)

We move all terms to the left:

4(k-2)-6-(4k-(3k-2))=0

We multiply parentheses

4k-(4k-(3k-2))-8-6=0



We calculate terms in parentheses: -(4k-(3k-2)), so:

4k-(3k-2)

We get rid of parentheses

4k-3k+2

We add all the numbers together, and all the variables

k+2

Back to the equation:

-(k+2)



We add all the numbers together, and all the variables

4k-(k+2)-14=0

We get rid of parentheses

4k-k-2-14=0

We add all the numbers together, and all the variables

3k-16=0

We move all terms containing k to the left, all other terms to the right

3k=16

k=16/3

k=5+1/3

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