n+(n+2)+(n+4)=-132

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Solution for n+(n+2)+(n+4)=-132 equation: 



n+(n+2)+(n+4)=-132

We move all terms to the left:

n+(n+2)+(n+4)-(-132)=0

We add all the numbers together, and all the variables

n+(n+2)+(n+4)+132=0

We get rid of parentheses

n+n+n+2+4+132=0

We add all the numbers together, and all the variables

3n+138=0

We move all terms containing n to the left, all other terms to the right

3n=-138

n=-138/3

n=-46

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