14*y*y-2=490

Solution for 14*y*y-2=490 equation:

14y*y-2=490

We move all terms to the left:

14y*y-2-(490)=0

We add all the numbers together, and all the variables

14y*y-492=0

Wy multiply elements

14y^2-492=0

a = 14; b = 0; c = -492;
Δ = b2-4ac
Δ = 02-4·14·(-492)
Δ = 27552
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{27552}=\sqrt{16*1722}=\sqrt{16}*\sqrt{1722}=4\sqrt{1722}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{1722}}{2*14}=\frac{0-4\sqrt{1722}}{28}
=-\frac{4\sqrt{1722}}{28}
=-\frac{\sqrt{1722}}{7}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{1722}}{2*14}=\frac{0+4\sqrt{1722}}{28}
=\frac{4\sqrt{1722}}{28}
=\frac{\sqrt{1722}}{7}
$