4(k+12)=-20

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Solution for 4(k+12)=-20 equation: 



4(k+12)=-20

We move all terms to the left:

4(k+12)-(-20)=0

We add all the numbers together, and all the variables

4(k+12)+20=0

We multiply parentheses

4k+48+20=0

We add all the numbers together, and all the variables

4k+68=0

We move all terms containing k to the left, all other terms to the right

4k=-68

k=-68/4

k=-17

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