15=3(k-11)

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Solution for 15=3(k-11) equation: 



15=3(k-11)

We move all terms to the left:

15-(3(k-11))=0



We calculate terms in parentheses: -(3(k-11)), so:

3(k-11)

We multiply parentheses

3k-33

Back to the equation:

-(3k-33)



We get rid of parentheses

-3k+33+15=0

We add all the numbers together, and all the variables

-3k+48=0

We move all terms containing k to the left, all other terms to the right

-3k=-48

k=-48/-3

k=+16

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