4(c+12)=68

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Solution for 4(c+12)=68 equation: 



4(c+12)=68

We move all terms to the left:

4(c+12)-(68)=0

We multiply parentheses

4c+48-68=0

We add all the numbers together, and all the variables

4c-20=0

We move all terms containing c to the left, all other terms to the right

4c=20

c=20/4

c=5

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