13(2x)+20=6(5x-2)

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Solution for 13(2x)+20=6(5x-2) equation: 



13(2x)+20=6(5x-2)

We move all terms to the left:

13(2x)+20-(6(5x-2))=0



We calculate terms in parentheses: -(6(5x-2)), so:

6(5x-2)

We multiply parentheses

30x-12

Back to the equation:

-(30x-12)



We get rid of parentheses

132x-30x+12+20=0

We add all the numbers together, and all the variables

102x+32=0

We move all terms containing x to the left, all other terms to the right

102x=-32

x=-32/102

x=-16/51

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