2(4x+10)=x-130

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Solution for 2(4x+10)=x-130 equation: 



2(4x+10)=x-130

We move all terms to the left:

2(4x+10)-(x-130)=0

We multiply parentheses

8x-(x-130)+20=0

We get rid of parentheses

8x-x+130+20=0

We add all the numbers together, and all the variables

7x+150=0

We move all terms containing x to the left, all other terms to the right

7x=-150

x=-150/7

x=-21+3/7

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