4(b+5)=20+4b

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Solution for 4(b+5)=20+4b equation:



4(b+5)=20+4b
We move all terms to the left:
4(b+5)-(20+4b)=0
We add all the numbers together, and all the variables
4(b+5)-(4b+20)=0
We multiply parentheses
4b-(4b+20)+20=0
We get rid of parentheses
4b-4b-20+20=0
We add all the numbers together, and all the variables
=0
b=0/1
b=0

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