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11/4x+27=3x
We move all terms to the left:
11/4x+27-(3x)=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
-3x+11/4x+27=0
We multiply all the terms by the denominator
-3x*4x+27*4x+11=0
Wy multiply elements
-12x^2+108x+11=0
a = -12; b = 108; c = +11;
Δ = b2-4ac
Δ = 1082-4·(-12)·11
Δ = 12192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12192}=\sqrt{16*762}=\sqrt{16}*\sqrt{762}=4\sqrt{762}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(108)-4\sqrt{762}}{2*-12}=\frac{-108-4\sqrt{762}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(108)+4\sqrt{762}}{2*-12}=\frac{-108+4\sqrt{762}}{-24} $
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