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(x)=1/2x+9
We move all terms to the left:
(x)-(1/2x+9)=0
Domain of the equation: 2x+9)!=0We get rid of parentheses
x∈R
x-1/2x-9=0
We multiply all the terms by the denominator
x*2x-9*2x-1=0
Wy multiply elements
2x^2-18x-1=0
a = 2; b = -18; c = -1;
Δ = b2-4ac
Δ = -182-4·2·(-1)
Δ = 332
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{332}=\sqrt{4*83}=\sqrt{4}*\sqrt{83}=2\sqrt{83}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{83}}{2*2}=\frac{18-2\sqrt{83}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{83}}{2*2}=\frac{18+2\sqrt{83}}{4} $
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