4(X+2)=4(X+1)-2(x-2)

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Solution for 4(X+2)=4(X+1)-2(x-2) equation: 



4(X+2)=4(X+1)-2(X-2)

We move all terms to the left:

4(X+2)-(4(X+1)-2(X-2))=0

We multiply parentheses

4X-(4(X+1)-2(X-2))+8=0



We calculate terms in parentheses: -(4(X+1)-2(X-2)), so:

4(X+1)-2(X-2)

We multiply parentheses

4X-2X+4+4

We add all the numbers together, and all the variables

2X+8

Back to the equation:

-(2X+8)



We get rid of parentheses

4X-2X-8+8=0

We add all the numbers together, and all the variables

2X=0

X=0/2

X=0

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