4(5+c)=3(1+c)

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Solution for 4(5+c)=3(1+c) equation: 



4(5+c)=3(1+c)

We move all terms to the left:

4(5+c)-(3(1+c))=0

We add all the numbers together, and all the variables

4(c+5)-(3(c+1))=0

We multiply parentheses

4c-(3(c+1))+20=0



We calculate terms in parentheses: -(3(c+1)), so:

3(c+1)

We multiply parentheses

3c+3

Back to the equation:

-(3c+3)



We get rid of parentheses

4c-3c-3+20=0

We add all the numbers together, and all the variables

c+17=0

We move all terms containing c to the left, all other terms to the right

c=-17

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