3(2x+1)5=(2x-5)

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Solution for 3(2x+1)5=(2x-5) equation: 



3(2x+1)5=(2x-5)

We move all terms to the left:

3(2x+1)5-((2x-5))=0

We multiply parentheses

30x-((2x-5))+15=0



We calculate terms in parentheses: -((2x-5)), so:

(2x-5)

We get rid of parentheses

2x-5

Back to the equation:

-(2x-5)



We get rid of parentheses

30x-2x+5+15=0

We add all the numbers together, and all the variables

28x+20=0

We move all terms containing x to the left, all other terms to the right

28x=-20

x=-20/28

x=-5/7

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