4(4z-3)+9=8+6(7z-2)

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Solution for 4(4z-3)+9=8+6(7z-2) equation: 



4(4z-3)+9=8+6(7z-2)

We move all terms to the left:

4(4z-3)+9-(8+6(7z-2))=0

We multiply parentheses

16z-(8+6(7z-2))-12+9=0



We calculate terms in parentheses: -(8+6(7z-2)), so:

8+6(7z-2)

determiningTheFunctionDomain
6(7z-2)+8

We multiply parentheses

42z-12+8

We add all the numbers together, and all the variables

42z-4

Back to the equation:

-(42z-4)



We add all the numbers together, and all the variables

16z-(42z-4)-3=0

We get rid of parentheses

16z-42z+4-3=0

We add all the numbers together, and all the variables

-26z+1=0

We move all terms containing z to the left, all other terms to the right

-26z=-1

z=-1/-26

z=1/26

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