3c-(c-3)=2(c+1)+2

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Solution for 3c-(c-3)=2(c+1)+2 equation: 



3c-(c-3)=2(c+1)+2

We move all terms to the left:

3c-(c-3)-(2(c+1)+2)=0

We get rid of parentheses

3c-c-(2(c+1)+2)+3=0



We calculate terms in parentheses: -(2(c+1)+2), so:

2(c+1)+2

We multiply parentheses

2c+2+2

We add all the numbers together, and all the variables

2c+4

Back to the equation:

-(2c+4)



We add all the numbers together, and all the variables

2c-(2c+4)+3=0

We get rid of parentheses

2c-2c-4+3=0

We add all the numbers together, and all the variables

-1!=0

There is no solution for this equation

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