2(b-3)+3(1-b)=6

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Solution for 2(b-3)+3(1-b)=6 equation:



2(b-3)+3(1-b)=6
We move all terms to the left:
2(b-3)+3(1-b)-(6)=0
We add all the numbers together, and all the variables
2(b-3)+3(-1b+1)-6=0
We multiply parentheses
2b-3b-6+3-6=0
We add all the numbers together, and all the variables
-1b-9=0
We move all terms containing b to the left, all other terms to the right
-b=9
b=9/-1
b=-9

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