4(4x+4)=19x+11-3x+5

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Solution for 4(4x+4)=19x+11-3x+5 equation: 



4(4x+4)=19x+11-3x+5

We move all terms to the left:

4(4x+4)-(19x+11-3x+5)=0

We add all the numbers together, and all the variables

4(4x+4)-(16x+16)=0

We multiply parentheses

16x-(16x+16)+16=0

We get rid of parentheses

16x-16x-16+16=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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