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5/4x-7/8x=30
We move all terms to the left:
5/4x-7/8x-(30)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 8x!=0We calculate fractions
x!=0/8
x!=0
x∈R
40x/32x^2+(-28x)/32x^2-30=0
We multiply all the terms by the denominator
40x+(-28x)-30*32x^2=0
Wy multiply elements
-960x^2+40x+(-28x)=0
We get rid of parentheses
-960x^2+40x-28x=0
We add all the numbers together, and all the variables
-960x^2+12x=0
a = -960; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-960)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-960}=\frac{-24}{-1920} =1/80 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-960}=\frac{0}{-1920} =0 $
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