4(4x+1)=3x-4(6-x)=+8

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Solution for 4(4x+1)=3x-4(6-x)=+8 equation: 



4(4x+1)=3x-4(6-x)=+8

We move all terms to the left:

4(4x+1)-(3x-4(6-x))=0

We add all the numbers together, and all the variables

4(4x+1)-(3x-4(-1x+6))=0

We multiply parentheses

16x-(3x-4(-1x+6))+4=0



We calculate terms in parentheses: -(3x-4(-1x+6)), so:

3x-4(-1x+6)

We multiply parentheses

3x+4x-24

We add all the numbers together, and all the variables

7x-24

Back to the equation:

-(7x-24)



We get rid of parentheses

16x-7x+24+4=0

We add all the numbers together, and all the variables

9x+28=0

We move all terms containing x to the left, all other terms to the right

9x=-28

x=-28/9

x=-3+1/9

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