4(x+3)+12=21-5(x+6)

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Solution for 4(x+3)+12=21-5(x+6) equation:



4(x+3)+12=21-5(x+6)
We move all terms to the left:
4(x+3)+12-(21-5(x+6))=0
We multiply parentheses
4x-(21-5(x+6))+12+12=0
We calculate terms in parentheses: -(21-5(x+6)), so:
21-5(x+6)
determiningTheFunctionDomain -5(x+6)+21
We multiply parentheses
-5x-30+21
We add all the numbers together, and all the variables
-5x-9
Back to the equation:
-(-5x-9)
We add all the numbers together, and all the variables
4x-(-5x-9)+24=0
We get rid of parentheses
4x+5x+9+24=0
We add all the numbers together, and all the variables
9x+33=0
We move all terms containing x to the left, all other terms to the right
9x=-33
x=-33/9
x=-3+2/3

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