2(3x-12)-6(5x-37)+3(7x+16)=10(2x+4)

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Solution for 2(3x-12)-6(5x-37)+3(7x+16)=10(2x+4) equation: 



2(3x-12)-6(5x-37)+3(7x+16)=10(2x+4)

We move all terms to the left:

2(3x-12)-6(5x-37)+3(7x+16)-(10(2x+4))=0

We multiply parentheses

6x-30x+21x-(10(2x+4))-24+222+48=0



We calculate terms in parentheses: -(10(2x+4)), so:

10(2x+4)

We multiply parentheses

20x+40

Back to the equation:

-(20x+40)



We add all the numbers together, and all the variables

-3x-(20x+40)+246=0

We get rid of parentheses

-3x-20x-40+246=0

We add all the numbers together, and all the variables

-23x+206=0

We move all terms containing x to the left, all other terms to the right

-23x=-206

x=-206/-23

x=8+22/23

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